(2c^2+c-3)(3c-1)=0

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Solution for (2c^2+c-3)(3c-1)=0 equation:


Simplifying
(2c2 + c + -3)(3c + -1) = 0

Reorder the terms:
(-3 + c + 2c2)(3c + -1) = 0

Reorder the terms:
(-3 + c + 2c2)(-1 + 3c) = 0

Multiply (-3 + c + 2c2) * (-1 + 3c)
(-3(-1 + 3c) + c(-1 + 3c) + 2c2 * (-1 + 3c)) = 0
((-1 * -3 + 3c * -3) + c(-1 + 3c) + 2c2 * (-1 + 3c)) = 0
((3 + -9c) + c(-1 + 3c) + 2c2 * (-1 + 3c)) = 0
(3 + -9c + (-1 * c + 3c * c) + 2c2 * (-1 + 3c)) = 0
(3 + -9c + (-1c + 3c2) + 2c2 * (-1 + 3c)) = 0
(3 + -9c + -1c + 3c2 + (-1 * 2c2 + 3c * 2c2)) = 0
(3 + -9c + -1c + 3c2 + (-2c2 + 6c3)) = 0

Combine like terms: -9c + -1c = -10c
(3 + -10c + 3c2 + -2c2 + 6c3) = 0

Combine like terms: 3c2 + -2c2 = 1c2
(3 + -10c + 1c2 + 6c3) = 0

Solving
3 + -10c + 1c2 + 6c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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